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Signals13 min read

RLC Resonance

See how inductive and capacitive effects cancel at one frequency and why the response can become sharply selective.

Mental model

Like pushing a swing at its natural rhythm, energy transfers efficiently at resonance. Resistance determines how quickly that stored energy is lost.

f₀bandwidthresponsefrequency
At resonance the response peaks around f₀; resistance determines the peak width and quality factor.
UNDERSTAND THE BEHAVIOR
01

Capacitors store energy in an electric field and inductors store energy in a magnetic field. In an RLC circuit, energy can move back and forth between these fields.

02

At the resonant frequency, inductive and capacitive reactances have equal magnitude and opposite sign. Their reactive effects cancel, leaving the resistance to dominate a series circuit.

03

Lower resistance means less energy is lost each cycle, producing a higher Q and narrower bandwidth. Real coils add winding resistance, so measured Q is always finite.

Why it matters

Resonance is used for tuning radios, selecting frequencies, impedance matching and creating oscillators.

Core ideas

  • At resonance, XL and XC have equal magnitude.
  • Series resonance gives minimum impedance; parallel resonance gives maximum impedance in the ideal model.
  • Quality factor Q describes how narrow and selective the resonance is.
Key equationsf0 = 1 / (2π√LC)Series Q = ω0L / RBandwidth: BW = f0 / Q
EXAMPLE

Worked example — resonant frequency and bandwidth

1Given L = 10 mH and C = 100 nF.

2f0 = 1/(2π√(0.01 × 100×10⁻⁹)) ≈ 5.03 kHz.

3If the series resistance is 10 Ω, Q = 2π × 5030 × 0.01 / 10 ≈ 31.6.

4Bandwidth ≈ 5030/31.6 ≈ 159 Hz.

Common mistake

A very high Q can create unexpectedly large internal voltages even when the applied source voltage is modest.

RememberAt resonance, XL and XC have equal magnitude.

Practice and check your understanding

Try each question before opening the worked answer.

1. For L = 10 mH and C = 1 μF, find the ideal LC resonant frequency.

Show answer and reasoning

LC = 0.01 × 0.000001 = 10⁻8. √LC = 0.0001. Therefore f0 = 1/(2π × 0.0001) ≈ 1591.5 Hz.

2. At series RLC resonance, does the circuit have zero impedance?

Show answer and reasoning

Not when resistance is present. Inductive and capacitive reactances cancel, leaving the series resistance. Current is limited by that resistance; component voltages can still be large.

Try the calculation

Open LC resonance calculator →

A related calculation tool, not a complete simulation of the circuit. Check its model and units.

Continue learning

  • Frequency & Phase — Connect period, frequency and phase to what you actually see on an oscilloscope.
  • Bode Plots — Read gain and phase across frequency without treating the graph as a mysterious set of slopes.

Technical references and further reading

References are for further study, not endorsements. Report an error or suggest an improvement.

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