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Power Electronics8–10 min read

Bootstrap High-Side Gate Drivers

Learn how a floating capacitor supplies a high-side N-channel MOSFET gate and why the method has duty-cycle limits.

Mental model

A bootstrap supply is a small rechargeable battery riding on the switch node: it charges while the node is low, then floats upward to lift the high-side gate above its moving source.

VDRVDbootCbootVBHOVSHIGH-SIDEQHVS / switch nodeQL+VDCfloating supply
The capacitor charges while the switch node is low, then floats upward to drive the high-side gate.
UNDERSTAND THE BEHAVIOR
01

An N-channel high-side MOSFET needs its gate several volts above its source. When the source rises toward the DC bus, a ground-referenced logic output can no longer maintain that positive VGS. A floating gate-driver supply solves this level-shifting problem.

02

In a bootstrap circuit, a diode charges the bootstrap capacitor from the driver supply when the switch node is low. When the high-side device is commanded on, the charged capacitor and high-side driver ride upward with the source, supplying gate charge while maintaining the required gate-to-source voltage.

03

A first capacitor estimate is Cboot ≥ Qtotal/ΔV, where Qtotal includes MOSFET gate charge plus driver and leakage demands over the high-side interval. Add design margin, account for capacitor bias derating and diode drop, then verify the driver's undervoltage threshold over worst-case temperature and timing.

04

A basic bootstrap cannot hold the high side on forever because the capacitor must periodically recharge and leakage slowly discharges it. Very high duty cycle, long on-time or startup with the switch node already high may require a charge pump, isolated supply or another high-side bias method.

Why it matters

Learn how a floating capacitor supplies a high-side N-channel MOSFET gate and why the method has duty-cycle limits.

Core ideas

  • The high-side gate drive floats with the switch node.
  • The capacitor normally recharges when the switch node is low.
  • Bootstrap size and maximum on-time come from charge balance, leakage and undervoltage limits.
Key equationsCboot ≥ Qtotal/ΔVVGS = Vgate − Vsource
EXAMPLE

Work through a practical example

1Assume 45 nC total required charge and allow 0.5 V bootstrap droop.

2The charge-balance minimum is 45 nC/0.5 V = 90 nF.

3Choose a larger practical value such as 220 nF only after checking voltage bias, leakage, diode drop and the driver's recommendation.

4Confirm that the operating pattern provides enough low-side or freewheel time to recharge it.

Common mistake

Assuming a bootstrap driver can produce continuous 100% high-side duty cycle without any refresh path.

RememberThe high-side gate drive floats with the switch node.
TEST YOUR UNDERSTANDING

Three quick checks

Choose one answer per question, then check your work. Each answer includes an explanation.

1. When does a basic bootstrap capacitor normally recharge?
2. Qtotal = 50 nC and allowed droop is 0.5 V. What is the charge-balance minimum Cboot?
3. Why is continuous 100% high-side duty difficult for a basic bootstrap?

Practice and check your understanding

Try each question before opening the worked answer.

1. Why must the high-side gate rise above the DC bus rail?

Show answer and reasoning

Its source rises near the bus when on, so the gate must be higher than the source by the required VGS.

2. What happens if the bootstrap capacitor droops below the driver threshold?

Show answer and reasoning

The high-side driver may enter undervoltage lockout or the MOSFET may be under-driven, increasing loss and preventing reliable operation.

Continue learning

Technical references and further reading

References are for further study, not endorsements. Report an error or suggest an improvement.

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