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Ohm's Law

Solve voltage, current, or resistance from the other two values.

V = I × R
Enter the known values. V is calculated automatically.
VoltageCalculated
12 V

Calculation steps

1Unknown selected: V
2Rearrange: V = I × R
3Substitute the known values to obtain V = 12 V
30 FORMULAS · PAGE 1/5

Searchable formula library

DC circuits · 01

Ohm's Law

V = I × R

Solve voltage, current, or resistance from the other two values.

DC circuits · 02

Electrical Power

P = V × I

Solve power, voltage, or current.

DC circuits · 03

Resistor Power

P = I²R = V²/R

Relate resistor power to voltage and resistance.

Energy · 04

Electrical Energy

E = P × t

Uses watt-hours when time is entered in hours.

Energy · 05

Electric Charge

Q = I × t

Uses coulombs when current is in amperes and time is in seconds.

DC circuits · 06

Voltage Divider

Vout = Vin × R₂/(R₁ + R₂)

Solve any one of the four divider variables.

ADVANCED LEARNING

Build intuition, not just formulas

Choose a topic and work through the physical idea, circuit behavior, equations and a realistic example.

34guided lessons
Analog8 min read

Operational Amplifiers

Learn why an op-amp tries to make its two input voltages equal and how that creates useful amplifiers.

Mental model

Think of the op-amp as an extremely sensitive controller. It watches the difference between + and − inputs, then moves its output hard enough to reduce that difference.

+−U1VinVoutRfRg
Vin enters the + input. Rf returns Vout to the − input, while Rg connects that node to ground. Closed-loop gain: 1 + Rf/Rg. Op-amp supply pins are omitted for clarity.Scroll sideways to view the complete circuit.
UNDERSTAND THE BEHAVIOR
01

An operational amplifier starts with an enormous open-loop voltage gain. Even a tiny difference between its two inputs would command a very large output, so using it without feedback usually drives the output into saturation.

02

Negative feedback returns part of the output to the inverting input. The output then settles at the value that makes the input difference extremely small. This is the origin of the useful approximation V+ ≈ V−; it is a consequence of feedback, not a universal property.

03

Always check the non-ideal limits after calculating the ideal answer: input common-mode range, output swing, gain-bandwidth product, slew rate and output current.

Why it matters

Op-amps appear in sensor conditioning, filters, control loops, audio circuits and ADC interfaces. Understanding feedback lets you analyze many different circuits with the same two ideal rules.

Core ideas

  • The input current is approximately zero in an ideal op-amp.
  • With negative feedback, V+ ≈ V− while the output stays inside the supply rails.
  • The surrounding resistors—not the huge open-loop gain—set the useful closed-loop gain.
Key equationsInverting: Av = −Rf / RinNon-inverting: Av = 1 + Rf / Rg
EXAMPLE

Worked example — non-inverting amplifier

1Given: Rf = 9 kΩ, Rg = 1 kΩ and Vin = 0.20 V.

2Gain: Av = 1 + 9/1 = 10.

3Output: Vout = 10 × 0.20 = 2.0 V.

4Check: a 2.0 V output must be possible with the chosen supply voltage.

Common mistake

Do not assume V+ equals V− when there is no negative-feedback path or when the output has already saturated.

RememberThe input current is approximately zero in an ideal op-amp.
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LEARN IN 3 STEPS

More than an answer

  1. 1
    Identify the variablesSeparate the known values from what you need to find.
  2. 2
    Check the unitsConvert values to V, A, Ω and F before calculating.
  3. 3
    Follow the workingCompare each step with your own solution.